http://defibrillatorsolutions.com/aed-blog/2009/12/help-with-finding-the-potential-difference/ Automated External Defibrillator (AED) Blog - Training, Success Stories and more... Tue, 13 Sep 2011 09:41:38 +0000 hourly 1 http://wordpress.org/?v=3.2.1 http://defibrillatorsolutions.com/aed-blog/2009/12/help-with-finding-the-potential-difference/comment-page-1/#comment-7554 Yugiantoro ヘリ ユギアントロ Fri, 04 Dec 2009 18:41:10 +0000 http://defibrillatorsolutions.com/aed-blog/2009/12/help-with-finding-the-potential-difference/#comment-7554 dQ = C dV dW = V dQ dW = V C dV integrate both sides, ∫ dW = ∫ V C dV W = ½ C V² + Constant initial condition, at V = 0, W = 0 0 = ½ C 0² + Constant Constant = 0 W = ½ C V² 350 = ½ (30 E-6) V² V = 4830.46 Volts dQ = C dV
dW = V dQ
dW = V C dV
integrate both sides,
∫ dW = ∫ V C dV
W = ½ C V² + Constant
initial condition, at V = 0, W = 0
0 = ½ C 0² + Constant
Constant = 0
W = ½ C V²
350 = ½ (30 E-6) V²
V = 4830.46 Volts

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