Help With Finding The Potential Difference?
A defibrillator is a device that applies a strong electric shock to the chest over a time interval of a few milliseconds. Electrodes called paddles, about 8 cm across and coated with conducting paste, are held against the chest on both sides of the heart. Assume an energy of 350 J is to be delivered from a 30.0 µF capacitor. To what potential difference must it be charged?
I have tried using the equation V=Q/C by using 350 J for the Q and 3e-5 F for C, but I don’t know if I have my units wrong or if I’m just going at the problem in the wrong way. The answer should come out in volts, but every answer I’ve tried, webassign has said is wrong.
Thanks for the help.
Related posts:
- Charge Of Potential Difference?
- The Electric Potential Energy Stored In The Capacitor Of A Defibrillator Is 77 J, And The Capacitance Is 125 µ?
- What Is The Potential Difference Across The Capacitor Plates?
- Electrical Energy And Potential Physics Q’s..not Sure If I Use Area Of A Cylinder For 1st Q (check Ans 4 Rest)
- Electrical Energy And Potential Physics Q’s..not Sure If I Use Area Of A Cylinder For 1st Q (check Ans 4 Rest)







December 4, 2009 @ 6:41 pm
dQ = C dV
dW = V dQ
dW = V C dV
integrate both sides,
∫ dW = ∫ V C dV
W = ½ C V² + Constant
initial condition, at V = 0, W = 0
0 = ½ C 0² + Constant
Constant = 0
W = ½ C V²
350 = ½ (30 E-6) V²
V = 4830.46 Volts