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	<title>Comments on: A Defibrillator Passes 18a Of Current Through The Torso Of A Person In 2.0ms.a) How Much Charge Moves During?</title>
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	<link>http://defibrillatorsolutions.com/aed-blog/2009/08/a-defibrillator-passes-18a-of-current-through-the-torso-of-a-person-in-2-0ms-a-how-much-charge-moves-during/</link>
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		<title>By: gp4rts</title>
		<link>http://defibrillatorsolutions.com/aed-blog/2009/08/a-defibrillator-passes-18a-of-current-through-the-torso-of-a-person-in-2-0ms-a-how-much-charge-moves-during/comment-page-1/#comment-2548</link>
		<dc:creator>gp4rts</dc:creator>
		<pubDate>Wed, 26 Aug 2009 21:27:16 +0000</pubDate>
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		<description>18A = 18 coul/sec.  The time is 2*10^-3 sec, so the total charge is A*t = 18*2*10^-3 coul = 3.6*10^-2 coul
Each electron carries a charge of 1.6*10^-19 coul, so the number of electrons is 3.6*10^-2 / 1.6*10^-19 = 2.25*10^17</description>
		<content:encoded><![CDATA[<p>18A = 18 coul/sec.  The time is 2*10^-3 sec, so the total charge is A*t = 18*2*10^-3 coul = 3.6*10^-2 coul<br />
Each electron carries a charge of 1.6*10^-19 coul, so the number of electrons is 3.6*10^-2 / 1.6*10^-19 = 2.25*10^17</p>
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