A Defibrillator Passes 18a Of Current Through The Torso Of A Person In 2.0ms.a) How Much Charge Moves During?
this time? b)how many electrons pass through the wires connected to the patient?
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August 26, 2009 @ 9:27 pm
18A = 18 coul/sec. The time is 2*10^-3 sec, so the total charge is A*t = 18*2*10^-3 coul = 3.6*10^-2 coul
Each electron carries a charge of 1.6*10^-19 coul, so the number of electrons is 3.6*10^-2 / 1.6*10^-19 = 2.25*10^17